The equation of the line represented by the following graph is y = 2/3x - 2.
What is slope intercept form of equation of straight line ?
The graph of the linear equation y = mx + c is a line with m as slope and c as the y-intercept. This form of the linear equation is called the slope-intercept form, and the values of m and c are real numbers.
How to calculate the slope of a straight line ?
Now slope is given by the formula ,
slope = (y2 - y1)/(x2 - x1)
where y2,y1 are the y-coordinates intercept of the graph and
x2,x1 are the x-coordinates intercept of the graph.
Calculating the equation of the straight line from the graph -
Here, from the graph , y2 = -2 ,
y1 = 0 ,
x2 = 3 and
x1 = 0 taking origin (0,0) as reference coordinate.
∴ Slope = (-2 - 0)/(3 - 0) = -2/3
As the straight line has negative slope,
thus slope(m) = 2/3
Now y-intercept is the point where the line cuts the y-axis in the graph.
By the problem, y-intercept (c) = -2
Thus putting the values of slope(m) and y-intercept (c) in the standard equation of straight line y = mx + c ,
Thus the equation of the line represented by the following graph is y = 2/3x - 2.
To learn more about equation of straight line, refer -
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