kyleemarie2003
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4. Part A. Find the value of x.
A) x=20
B) x=35
C) x=70
D) x=110

Part B. Find the measure of the unlabeled angle in the previous question.
A) 40°
B) 70°
C) 110°
D) 140°

4 Part A Find the value of xA x20B x35C x70D x110Part B Find the measure of the unlabeled angle in the previous questionA 40B 70C 110D 140 class=

Respuesta :

Part A: B)35
As the angle y° equals to angle 2x°, y=2x.
And the sum of the angle (x+y+5°)and the angle 2x° is 180°.Therefore,
x+y+5°+2x =180°
x+2x+5°+2x=180°
5x+5° =180°
5x =175°
x =35°


Part B: C)110°
As I said, y =2x
And the unlabled angle eaquals to the angle(x+y+5°).
Therefore,
the unabled angle= x+y+5°
=x+2x+5°
=3x+5°
=3(35°)+5°
=110°
sid071

Hey there!!

The measure of the unlabeled angle is ( x + y - 5 ) due to the vertically opposite angles.

We also know 2x = y due to vertically opposite angles

If we add up all the angles, we get 360 degrees.

Hence,  

y + 2x + x + y - 5 + x + y - 5 = 360

4x + 3y - 10 = 360

Add 10 on both sides

4x + 3y = 370

We know 2x = y

Hence,

4x + 3y = 370 can be broken down as ,

4x + y + y + y = 370

4x + 2x + 2x + 2x = 370

10x = 370

x = 370 / 10

x = 37

The unknown angle = x + y - 5

x + 2x - 5

3x - 5

3 ( 37 ) - 5

111 - 5

106

Hence, the unknown angle is 106°

Hope my answer helps!!



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