The Perimeter of triangle ABC is 32.312
For us to get the perimeter of triangle ABC, we need to get the sides BC and AC using the sine rule
According to the rule
AB/sinC = BC/sinA
9/sin45 = BC/sin60
9√2 = BC/0.8660
BC = 9√2 * 0.8660
BC = 11.022
Similarly;
AC/sinB = 9/sin45
AC/sin75 = 9√2
AC = 9√2sin75
AC= 12.29
Perimeter of ABC = AB + BC + AC
Perimeter of ABC = 11.022 + 12.29 + 9
Perimeter of ABC = 32.312
Hence the Perimeter of triangle ABC is 32.312
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