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A stadium has 50 comma 00050,000 seats. Seats sell for ​$3030 in Section​ A, ​$2424 in Section​ B, and ​$1818 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1 comma 288 comma 8001,288,800 from each​ sold-out event. How many seats does each section​ hold?

Respuesta :

A= B+C

As given, A+B+C = 50000 seats

A+(B+C) = 50000

2A = 50000

A= 25000 seats

Now section A sells seats at $30 each

So, [tex]25000\times30=750000[/tex]

Now, B+C = 25000

B = 25000-C

B sells at $24 and C sells at $18

So, 24B+18C = 538800

Now as section A incurs an amount of $750000 from booking, so B and C will incur 1288800-750000 = 538800 where $1288800 is the total booking amount.

24B+18C = 538800

[tex]24(25000-C)+18C=538800[/tex]

[tex]600000-24C+18C=538800[/tex]

6C = 61200

C = 10200

Now, B = 25000-C

B = 25000 - 10200 = 14800

Hence, section A has 25000 seats

Section B has 14800 seats

Section C has 10200 seats




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