The answers to the given question are:
i. The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.
ii. The miners elevator is deeper than that of the equipment.
The speed of an object is the rate at which the object moves.
i.e speed = [tex]\frac{distance}{time}[/tex]
Thus,
Speed of the equipment elevator = 4 feet per second
Speed of the miners elevator = 15 feet per second.
Time of descent of the equipment elevator = 30 + 14
= 44 seconds
So that, the distance of the elevator at this time is;
speed = [tex]\frac{distance}{time}[/tex]
⇒ distance = speed x time
= 4 x 44
= 176
distance = - 176 feet
The distance of the miners elevator after 14 seconds is:
speed = [tex]\frac{distance}{time}[/tex]
⇒ distance = speed x time
= 15 x 14
= 210
distance = - 210 feet
Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.
Therefore, the miners elevator is deeper than that of the equipment.
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