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According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from 0.20 m/s to 0.32 m/s during a period of 0.08 s . What is the magnitude of the force exerted by the heart muscle?

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Blacklash

Answer:

    Magnitude of the force exerted by the heart muscle  = 0.03 N

Explanation:

  We have force = mass * acceleration

   Acceleration = Rate of change of velocity = Change in velocity/time = (0.32-0.20)/0.08

                          = 0.12/0.08 = 12/8 = 1.5 [tex]m/s^2[/tex]

   Mass of blood = 20 g = 20/1000 kg = 0.02 kg

   Magnitude of the force exerted by heart muscle = 0.02*1.5 = 0.03 N

pstnonsonjoku

The magnitude of the force exerted by the heart muscle is 0.03 N.

From Newton's second law, we know that F = ma

Where;

F = force

m = mass of the body

a = acceleration

Now we must find the acceleration from:

a = v - u/t

a = acceleration

v = final velocity

u = initial veocity

t = time taken

Substituting values;

a = 0.32 m/s -  0.20 m/s/ 0.08 s

a = 1.5 m/s^2

Since F = ma

But m was given in grams and we must convert to kilograms so m = 0.002 Kg

Therefore;

F = 0.002 Kg × 1.5 m/s^2

F = 0.03 N

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