Respuesta :
Hey There!:
Molar mass O2 => 32.0 g/mol
Molar mass Cl2 => 71.0 g/mol
effusion rate α 1 / (√ molar mass )
E Cl2 / E O2 = √ molar mass O2 / √ molar mass Cl2
E Cl2 / E O2 = ( √ 32.0 ) / ( √ 71.0 )
=> 0.671
Hope that helps!
Answer: The ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671
Explanation:
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
[tex]\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]
We are given:
Molar mass of chlorine gas = 71 g/mol
Molar mass of oxygen gas = 32 g/mol
By taking their ratio, we get:
[tex]\frac{Rate_{Cl_2}}{Rate_{O_2}}=\sqrt{\frac{M_{O_2}}{M_{Cl_2}}}[/tex]
[tex]\frac{Rate_{Cl_2}}{Rate_{O_2}}=\sqrt{\frac{32}{71}}\\\\\frac{Rate_{Cl_2}}{Rate_{O_2}}=0.671[/tex]
Hence, the ratio of rate of effusion of chlorine gas and oxygen gas will be 0.671
