Hey there!:
1 mole of FeSO4 = 151.8 g/mol
25.0 g change to mole = 25.0 / 151.8
moles of FeSO4 = 0.165 moles
One mole of any substance has 6.02*10²³ units
0.165 moles to get the number of Fe ( II ) ions :
number of Fe(II) ion = 0.165 * ( 6.02*10²³ )
number of Fe ( II ) ion = 9.93*10²² units
Answer:
[tex]ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}[/tex]
Explanation:
Hello,
In this case, the following mole-mass relationship, is applied to obtain the ions of iron (II) in 25.0 g of iron (II) sulfate whose molar mass is 152 g/mol:
[tex]ions_{Fe^{2+}}=25.0gFeSO_4*\frac{1molFeSO_4}{152gFeSO_4}*\frac{1molFe^{2+}}{1molFeSO_4}*\frac{6.022x10^{23}ionsFe^{2+}}{1molFe^{2+}} \\ions_{Fe^{2+}}=9.90x10^{22}ionsFe^{2+}[/tex]
Best regards.
