To solve this problem, we're going to have to use the equation: E=hv
This equation tells us that the energy of a particle of light (E), called a photon, is proportional to its frequency (v), by a constant factor (h). That constant (Planck's constant) we know to be 6.626 × 10^-34 J·s. So, we can plug in the frequency and Planck's constant to solve for the energy (E).
E=( 6.626 × 10^-34 J·s)(7.29 × 10^14 hz)
E= 4.830354 × 10^-19
Round to 3 significant figures, and you're done!
E= 4.83 × 10^-19
Answer:
[tex]4.83\times 10^{-19} J[/tex] is the energy of exactly one photon of this light.
Explanation:
Frequency of the blue shade light = [tex]\nu =7.29\times 10^{14} Hz[/tex]
Energy of the photon is given by Planck's equation = E
[tex]E=h\nu[/tex]
h = Planck's constant = [tex]6.634\times 10^{-34} Js[/tex]
[tex]E=6.634\times 10^{-34} Js\times 7.29\times 10^{14} s^{-1}[/tex]
[tex]E=4.83\times 10^{-19} J[/tex]
[tex]4.83\times 10^{-19} J[/tex] is the energy of exactly one photon of this light.
