The cell model below shows 2 solutions separated by a selectively permeable membrane indicated by the red dashed line.

What will most likely occur in this case?

The number of molecules on side A will increase and decrease on side B
The water level on side A will increase, but remain the same on side B.
The water level will increase on side B and decrease on Side A until concentrations are equalized.
The water level and number of particles will equalize on both sides of the membrane.

So naturally, Water loves to be with water. This is just a common knowledge of biology. The side with the least amount of water will recognize that the opposing side has more water. Water molecules in Side A will essentially try and cross the selectively permeable membrane and go onto the crowded side. This will make the Cell in A become lysed and it will shrink. Your answer will be:

C. The Water level will increase on side B and decrease on Side A until concentrations are equalized.

topeadeniran2 topeadeniran2 · Answer 2 · 2021-11-04T21:46:42+01:00

The most likely to occur in this case will be C. The water level will increase on side B and decrease on Side A until concentrations are equalized.

A permeable membrane is vital as it allows for the passage of water in a solution. Based on the diagram, the water molecules that are in Side A will try and cross the permeable membrane to side B.

This will therefore lead to less water in cell A and thus it becomes lysed and it will shrink. Therefore, the water level will increase on side B and decrease on Side A until concentrations are equalized.

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