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PLEASE HELP!!!!WILL GIVE BRAINIEST TO WHOEVER ANSWERS  
1. Suppose the path of a golf ball, in a chip shot from a small hill, follows the path graphed by the quadratic function ƒ(d) = –1.6d2 + 3.3d + 0.2 where d is the horizontal distance the ball travels, and ƒ(d) is the height, in meters, of the ball at d horizontal distance. Find the total horizontal distance the ball traveled while in the air.

A. 2.12 meters horizontally
B. 2.26 meters horizontally
C. 1.84 meters horizontally
D. 2.95 meters horizontally

2. Suppose the path of a golf ball, in a chip shot, follows the path graphed by the quadratic function ƒ(d) = –1.6d2 + 3.3d + 0.2 where d is the horizontal distance the ball travels, and ƒ(d) is the height, in meters, of the ball at d horizontal meters. Identify the domain and range that matches this situation.

A. Domain: [0,2.07] horizontal meters; range: [0, 1.72] vertical meters
B. Domain: [0,2.07] horizontal meters; range: [0, 1.72] vertical meters
C. Domain: [0,2.12] horizontal meters; range: [0, 1.90] vertical meters
D. Domain: [0,2.07] horizontal meters; range: [0, 1.72] vertical meters

Respuesta :

remotecontrolbrain

1. First calculate the positive root of the quadratic using your preferred formula. I got a solution [tex]d = 1/32 (33 + \sqrt{1217})=2.121...[/tex]. That gives you the distance the ball traveled from d=0 (small hill). So the answer is A.

2. The domain is [0,2.121...]. The range is from 0 to the max height. The d for which the ball is the highest is given by the formula x = -b / 2a = -3.3/(-3.2) = 1.031... so the max is 1.902... So the range is [0,1.902...] So the answer is C.