Respuesta :

Let's solve your equation step-by-step.

4c2+7c−5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

−b±√b2−4ac

2a

c=

−(7)±√(7)2−4(4)(−5)

2(4)

c=

−7±√129

8

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

√129

Answer:

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

√129Let's solve your equation step-by-step.

4c2+7c−5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

−b±√b2−4ac

2a

c=

−(7)±√(7)2−4(4)(−5)

2(4)

c=

−7±√129

8

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

√129

Answer:

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

√129Let's solve your equation step-by-step.

4c2+7c−5=0

Step 1: Use quadratic formula with a=4, b=7, c=-5.

c=

−b±√b2−4ac

2a

c=

−(7)±√(7)2−4(4)(−5)

2(4)

c=

−7±√129

8

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

√129

Answer:

c=

−7

8

+

1

8

√129 or c=

−7

8

+

−1

8

  • √129