5 units right: x + 5
1 unit up: y + 1
(x, y) → (x + 5, y + 1)
(4, 2) → (4 + 5, 2 + 1) = (9, 3)
(3, 7) → (3 + 5, 7 + 1) = (8, 8)
[tex]\begin{array}{ccc}\ \ x&y\end{array}\ \ \ \ \begin{array}{ccc}\ \ x&y\end{array}\\\left[\begin{array}{ccc}4&2\\3&7\end{array}\right]+\left[\begin{array}{ccc}5&1\\5&1\end{array}\right]=\left[\begin{array}{ccc}9&3\\8&8\end{array}\right][/tex]
Answer:
[tex]\left[\begin{array}{ccc}4&2\\3&7\end{array}\right]+\left[\begin{array}{ccc}5&1\\5&1\end{array}\right][/tex]
