A skyboarder shoots off a ramp with a velocity of 6.6m/s.
Directed at an angle of 58° above the horizontal.
The end of the ramp is 1.2m above the ground.
The skateboarder experiences a gravitational acceleration of 10m/s²
Time taken to reach the maximum height = Velocity ÷ Acceleration = 6.6m/s ÷ 10m/s² = 0.66s
Distance covered from the starting point = Velocity × Time = 6.6m/s × 0.66s = 4.356m
Let (h) be the highest point above the ground that the skateboarder reaches.
[tex]\frac{h}{4.356m}[/tex] = Sin 58°
Height (h) = Sin 58° × 4.356m = 3.694m (rounded up to three decimal places).
Let the horizontal distance between starting point and the highest point reached be (b).
[tex]\frac{b}{4.356m}[/tex] = Cos 58°
b = 4.356m × Cos 58° = 2.308m (rounded up to three decimal places)
