So firstly, the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
[tex](2n^2 + 2n + 3n + 3)(4n - 5)[/tex]
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
[tex](2n(n+1)+3(n+1))(4n-5)[/tex]
Now we can rewrite this expression as [tex](2n+3)(n+1)(4n-5)[/tex] , which is your final answer.
