11x + y = 4
x | y
0 | 4
[tex]\frac{4}{11}[/tex] | 0
plot the y-intercept (0, 4) and the x-intercept ([tex]\frac{4}{11}[/tex], 0)
or
11x + y = 4
-11x -11x
y = -11x + 4 ⇒ m = [tex]\frac{-11}{1}[/tex], b = 4
plot at point the y-intercept "b = 4" (0,4). plot the next point using the slope "m = [tex]\frac{-11}{1}[/tex]" from point (0,4), count down 11 and to the right 1 (1,-7).
Using intercepts would not provide an accurate graph because you have to estimte where ([tex]\frac{4}{11}[/tex], 0) is, so it is best to use slope-intercept form.
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x + y = -2
x | y
0 | -2
-2 | 0
plot the y-intercept (0, -2) and the x-intercept (-2, 0)
or
x + y = -2
-x -x
y = -x - 2 ⇒ m = [tex]\frac{-1}{1}[/tex], b = -2
plot at point the y-intercept "b = -2" (0,-2). plot the next point using the slope "m = [tex]\frac{-1}{1}[/tex]" from point (0,-2), count down 1 and to the right 1 (1,-3).
Both methods are easy to use so either can be used.
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x - 2y = 18
x | y
0 | -9
18 | 0
plot the y-intercept (0, -9) and the x-intercept (18, 0)
or
x - 2y = 18
-x -x
-2y = -x + 18
[tex]\frac{-2y}{-2} = \frac{-1}{-2}x + \frac{18}{-9}[/tex]
y = [tex]\frac{1}{2}x[/tex] - 9
plot at point the y-intercept "b = -9" (0,-9). plot the next point using the slope "m = [tex]\frac{1}{2}[/tex]" from point (0,-9), count up 1 and to the right 2 (2,-8).
Using intercepts will make a large graph since you have to plot (18,0) so it is best to use the slope-intercept form.
