Math! Help me out on one of these?

(23) x = 800 × tan70°
using the tan ratio in the right triangle
tan 70° = [tex]\frac{x}{800}[/tex]
⇒ x = 800 × tan 70°
(24) using the tan ratio in the right triangle
tan80° = [tex]\frac{d}{30}[/tex]
⇒ d = 30 × tan80°
(25) [tex]\frac{5.6}{2}[/tex] = [tex]\frac{h}{6}[/tex] ( h is the height of the cross )
using similar triangles, with 2yards = 6 feet
#23) in reference to the given angle, which sides are given? opposite & adjacent
tan θ = [tex]\frac{opposite}{adjacent}[/tex]
tan 70° = [tex]\frac{x}{800}[/tex]
800 tan 70° = x
2,197.98 = x
Answer: 2,198
#24) in reference to the given angle, which sides are given? opposite & adjacent
tan θ = [tex]\frac{opposite}{adjacent}[/tex]
tan 80° = [tex]\frac{d}{30}[/tex]
30 tan 80° = x
170.138 = x
Answer: 170 ft
#26) first convert everything into the same units. I am going to use feet
5 ft 6 inches = 5.5 ft
2 yards = 6 ft
Next, set up a proportion, cross multiply, and solve for the variable
[tex]\frac{height(boy)}{shadow (boy)} = \frac{height(cross)}{shadow (cross)}[/tex]
[tex]\frac{5.5}{2} = \frac{x}{6}[/tex]
5.5(6) = 2(x)
[tex]\frac{5.5(6)}{2} = x[/tex]
5.5(3) = x
16.5 = x
Answer: 16.5 ft