contestada

A helicopter above the ground is descending at 3.1 m/s it drops a package from rest relative to the helicopter just before it hits the ground the package is falling at a rate of 9.5 m/s relative to the helicopter find the velocity of the package relative to the ground.
12.6 m/s, up
6.4 m/s up
12.6 m/s down
6.4 m/s down

Respuesta :

Initial speed of the package will be same as the speed of helicopter as it has been dropped from the helicopter.

So if we find the velocity of package relative to helicopter then it will be zero

so here we can say

[tex]v_i = v_{helicopter} = 3.1 m/s[/tex]

Now here relative velocity of the of the package will increase due to free fall in gravity and then just before if hit the ground the speed of the package will be 9.5 m/s relative to the helicopter.

so here we can say

[tex]v_{p/H} = v_p - v_H[/tex]

[tex]v_{p/H} = 9.5 m/s[/tex]

[tex]v_H = 3.1 m/s[/tex]

so here the net velocity with respect to ground will be

[tex]v_p = V_{p/H} + v_H[/tex]

[tex]v_p = 3.1 + 9.5 = 12.6 m/s[/tex]

so package will hit with speed 12.6 m/s downwards

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