the equation y+6=1/3(x-9) is written in point-slope form. What is the equation written in slope-intercept form?

A. y= 1/3x-3
B. y=1/3x+9
C.y=1/3x-9
D. y=1/3x+3

Respuesta :

y+6=1/3(x-9)

Moved all terms from left to right that doesn't contain y

Y=-6 +1/3x-3

Simplify

Y=1/3x-9


Your answer is c.

Answer: [tex]y=\dfrac{1}{3}x-9[/tex]

Step-by-step explanation:

The equation of a line in slope -intercept form is written as :-

[tex]y=mx+c[/tex]

The given equation : [tex]y+6=\dfrac{1}{3}(x-9)[/tex]

To write the given equation in slope - intercept form , we need to first solve the right -hand sides in the equation.

[tex]y+6=\dfrac{1}{3}(x-9)\\\\\Rightarrow\  [tex]y+6=\dfrac{1}{3}x-3\\\\\Rightarrow\ y=\dfrac{1}{3}x-3-6\\\\\Rightarrow\ y=\dfrac{1}{3}x-9[/tex]

Hence, the equation written in slope-intercept form :  [tex]y=\dfrac{1}{3}x-9[/tex]