The quadratic function is given by the equation [tex]h(t)=-0.075t^2+0.6t+2.5.[/tex]
The maximal height will be at vertex. Find t-coordinate of the parabola vertex:
[tex]t_{vertex}=-\dfrac{b}{2a}=-\dfrac{0.6}{2\cdot (-0.075)}=4\text{ seconds.}[/tex]
At t=4,
[tex]h(4)=-0.075\cdot 4^2+0.6\cdot 4+2.5=-1.2+2.4+2.5=3.7\text { feet. }[/tex]
Answer: it will take 4 seconds for the ball to reach the maximal height of 3.7 feet.
