Respuesta :
assuming you mean y² = 169
then taking the square root of both sides gives
y = [tex]\sqrt{169}[/tex] = ± 13
since 13² = 169 and (- 13)² = 169
The values of y are -13 and 13 in the equation y^2 = 169.
It is given that the expression [tex]\rm y^2 = 169[/tex]
It is required to find the values of y.
What is a quadratic equation?
Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We have a quadratic equation:
[tex]\rm y^2 = 169[/tex]
[tex]\rm y^2-169=0[/tex] (subtract 169 on both sides)
[tex]\rm y^2- 13^2=0[/tex] (169 = 13²)
(y+13)(y-13) = 0 (a²-b² = (a+b)(a-b))
Taking (y+13) = 0 ⇒ y = -13
Taking (y-13) = 0 ⇒ y = 13
Thus, the values of y are -13 and 13 in the equation y^2 = 169.
Learn more about quadratic equations here:
brainly.com/question/2263981
