Respuesta :

Dejanras

Balanced chemical reaction:

2FeBr₃(aq) + 3Na₂S(aq) → Fe₂S₃(s) + 6NaBr(aq).

Ionic reaction:

2Fe³⁺(aq) + 3Br⁻(aq) + 6Na⁺(aq) + 3S²⁻(aq) → Fe₂S₃(s) + 6Na⁺(aq) + 6Br⁻(aq).

Net ionic reaction: 2Fe³⁺(aq) + 3S²⁻(aq) → Fe₂S₃(s).

FeBr₃ - iron(III) bromide.

Na₂S - sodium sulfide.

Fe₂S₃ - iron(III) sulfide.

NaBr - sodium bromide.

JannetPalos

Answer:

Net ionic equation is [tex]2Fe^{3+}(aq.)+3S^{2-}(aq.)\rightarrow Fe_{2}S_{3}(s)[/tex]

Explanation:

First write total ionic equation and then remove spectator ions from both side of equation to get net ionic equation. To write total ionic equation, separate all aqueous species into their constituting ions.

Total ionic equation-

[tex]6Na^{+}(aq.)+3S^{2-}(aq.)+2Fe^{3+}(aq.)+6Br^{-}(aq.)\rightarrow Fe_{2}S_{3}(s)+6Na^{+}(aq.)+6Br^{-}(aq.)[/tex]

Here [tex]Na^{+}and Br^{-}[/tex] are spectator ions as they are presnt on both side of equation.

Hence net ionic equation is [tex]2Fe^{3+}(aq.)+3S^{2-}(aq.)\rightarrow Fe_{2}S_{3}(s)[/tex]