An astronaut takes her bathroom scales to the moon, where g = 1.6 m/s2. On the moon, compared to at home on earth?
Would it be mass is the same but weight is less??

Respuesta :

Answer

Yes, the mass would not change, but the weight would, and it would be smaller on the moon because the acceleration of gravity is much less.

Explanation

If the definition of weight is:

W = mg

where:

m = mass

g = acceleration of gravity.

So, suppose we measure the weight of an object whose mass is

m = 50kg

The weight on earth would be:

[tex]W = 50kg * 9.8\frac{m}{s^2} = 490 N[/tex]

The weight on the moon would be:

[tex]W = 50kg * 1.62\frac{m}{s^2} = 81 N[/tex]

As you can see in both cases the mass was the same = 50kg but the weight is much higher on the earth

Yes, the mass of the astronaut’s bathroom is same but its weight will be less on the moon.

Further explanation:

First of all we will know about the mass and weight,

Mass: Mass of an object is its quantity or amount of inertia.

It remains constant and does not affected by change in the gravity.

Weight: Weight of an object is the amount of force experienced by the object when it comes in a gravitational field. If there is no gravitational field then there will be no weight of the object but the mass of the object will remain same.  

It is also a type of force.

Weight of the object can be calculated as,

[tex]\boxed{W = mg}[/tex]  

Here, [tex]W[/tex] is the weight of the object, [tex]m[/tex] is the mass of the object and [tex]g[/tex] is the acceleration due to gravity.

Consider that the mass of the astronaut’s bathroom is [tex]20{\text{ kg}}[/tex].

So, its weight on the earth will be,

[tex]{W_e} = 20{g_e}[/tex]

 

Here, [tex]{g_e}[/tex] is the value of acceleration due to gravity of earth and its value is [tex]9.8{\text{ }}{{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}^2}[/tex] .

Substitute this value in above equation.

[tex]\begin{aligned}{W_e}&=20\times9.8\\&=196{\text{N}}\\\end{aligned}[/tex]

 

Now, we will calculate it weight on the moon.

[tex]{W_m} = m{g_m}[/tex]

 

Here, [tex]{g_m}[/tex] is the value of moon’s gravity and its value is given as [tex]1.6{\text{ }}{{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}^2}[/tex].

Substitute this value of [tex]{g_m}[/tex] in above equation.

[tex]\begin{aligned}{W_m}&=20\times 1.6\\&=32{\text{N}}\\\end{aligned}[/tex]

 

Here, we can see the weight of the astronaut’s bathroom is more on earth as compare to moon.

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Answer detail:

Grade: High School

Subject: Physics

Chapter: Gravitation

Keywords:

Astronaut, bathroom, weight, moon, earth, mass, change, unchanged, constant, gravitation, force, quantity, same, acceleration due to gravity, force, acceleration.