Answer:- work = 319 J
Solution:- The volume of the gas decreases from 5.35 L to 1.55 L.
[tex]\Delta V=1.55L-5.35L[/tex] = -3.80 L
external pressure is given as 0.829 atm.
[tex]w=-P_e_x_t\Delta V[/tex]
where w is representing work.
Let's plug in the values and calculate pressure-volume work:
[tex]w=-0.829atm(-3.80L)[/tex]
w = 3.15 atm.L
We need to convert atm.L to J.
1 atm.L = 101.325 J
So, [tex]3.15atm.L(\frac{101.325J}{1atm.L})[/tex]
= 319 J
So, 319 J of work is involved in a chemical reaction. Positive work means the work is done on the system.
