Answer:
Option D
the weights would be the best deal is [tex]2\frac{7}{8}[/tex]
Step-by-step explanation:
The price of all meat packages are marked $12.99.
To find the best deal we have to show that the weight of which package will be greatest.
The weight of each packages are written as a mixed fraction as follows;
[tex]2\frac{2}{3} , 2\frac{9}{11} , 2\frac{4}{5} , 2\frac{7}{8}[/tex]
Now, convert these improper fraction into proper fraction.
[tex]2\frac{2}{3}=\frac{8}{3}[/tex]
[tex]2\frac{9}{11}=\frac{31}{11}[/tex]
[tex]2\frac{4}{5}=\frac{24}{5}[/tex]
[tex]2\frac{7}{8}=\frac{23}{8}[/tex]
To make their denominators same,
the LCM(Least common multiples) of the denominators(11, 3, 5, 8) is 1320.
So,
[tex]\frac{8}{3}= \frac{8\cdot 440}{3\cdot 440} =\frac{3520}{1320}[/tex]
[tex]\frac{31}{11}= \frac{31\cdot 120}{11\cdot 120} =\frac{3720}{1320}[/tex]
[tex]\frac{14}{5} =\frac{14\cdot 264}{5\cdot 264}= \frac{3696}{1320}[/tex]
[tex]\frac{23}{8}=\frac{23\cdot 165}{8\cdot 165} =\frac{3795}{1320}[/tex]
As, you can see that the only fraction is greatest is [tex]\frac{3795}{1320}[/tex]
therefore, the weight [tex]2\frac{7}{8}[/tex] would be the best deal.