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Which exponential function has an initial value of 2?

A) f(x) = 2(3^x)
B) the first picture
C) f(x) = 3(2^x)
D) the last picture

Which exponential function has an initial value of 2 A fx 23x B the first picture C fx 32x D the last picture class=
Which exponential function has an initial value of 2 A fx 23x B the first picture C fx 32x D the last picture class=

Respuesta :

A) f(x) = 2(3^x) is the answer

Answer:

The correct option is A) [tex]f(x)=2(3^{x})[/tex] has an initial value of 2 .

Step-by-step explanation:

We need to find the exponential function has an initial value of 2

To check function which has an initial value of 2, we put [tex]x=0[/tex]

Check for A) [tex]f(x)=2(3^{x})[/tex]

Put x=0

[tex]f(0)=2(3^{0})[/tex]

[tex]f(0)=2[/tex]

so, this is the function has an initial value of 2

Therefore, the correct option is A) [tex]f(x)=2(3^{x})[/tex] has an initial value of 2 .

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