contestada

Part 1: Create an equation of a line in point-slope form. Be sure to identify all parts of the equation before writing the equation.
Part 2: Using the equation of the line you wrote in part 1, write an equation of a line that is perpendicular to this line.

Respuesta :

Answer with explanation:

Part--1:

We know that a equation in point-slope form is represented by:

               [tex]y-y_1=m(x-x_1)[/tex]

where m is the slope of the line and [tex](x_,y_1)[/tex] is a point through which the line passes.  

  Consider a equation in a point-slope form as:

           [tex]y-5=2(x-1)[/tex]

This means that the slope of the line is: 5

and the line  passes through the point (1,5).

Part--2:

Now as we know that if a line has a slope as m then the perpendicular line has a slope: -1/m

Since,

[tex]m\times \text{Slope\ of\ second\ line}=-1\\\\i.e.\\\\\text{Slope\ of\ second\ line}=\dfrac{-1}{m}[/tex]

Let this perpendicular line passes through (2,6)

Hence, the equation of a line in point slope form is given by:

             [tex]y-6=\dfrac{-1}{2}(x-2)[/tex]

Answer:

Equation:

y-y1=m(x-x1)

y-2=4(x-1)

Part 2:

y=-1/4x +b

Step-by-step explanation:

Otras preguntas