find the range of the following peicewise functiom

f(x) = x + 4 ; -4 ≤ x < 3
f(-4) = (-4) + 4
= 0
f(3) = (3) + 4
= 7
R: 0 ≤ y < 7 ⇒ [0, 7)
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f(x) = 2x - 1 ; 3 ≤ x < 6
f(3) = 2(3) - 1
= 6 - 1
= 5
f(6) = 2(6) - 1
= 12 - 1
= 11
R: 5 ≤ y < 11 ⇒ [5, 11)
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Now, put them together: [0, 7) U [5, 11) = [0, 11)
Answer: B
answer is [0,11)
f(x) = x+4 is the first function
We plug in -4 for x in f(x) = x+4
f(-4) = -4 + 4 = 0
So the graph starts at (-4,0)
Now plug in 3 for x in f(x) = x+4
f(3) = 3 + 4 = 7
So the first function ends at (3,7)
Second function is f(x) = 2x - 1
We plug in 3 for x in f(x) = 2x-1
f(3) =2(3)-1 = 5
So the second graph starts at (3,5)
We plug in 6 for x in f(x) = 2x-1
f(6) =2(6)-1 = 11
So the second graph ends at (6,11)
3<=x<6 so 6 is excluded from x
The range of the following piece wise function is 0 to 11
answer is [0,11)