The wings of the model will be 0.4396ft long
Explanation.
We convert the scale [tex]1in:40ft [/tex] so we can obtain the scale in the same units.
We know that,
1 foot =12 inches. This implies that
[tex]1inch=\frac{1}{12}[/tex] ft
[tex]\frac{1}{12}:40[/tex] ft
Let us multiplyeach term in the ratio by 12
Tis implies the scale is 1:480
Since 211 is less than 480 we divide to obtain length of
wing of model to be
[tex]\frac{211}{240}=0.4396[/tex]ft
Answer: The wings of the model will be 5.275 in
Step-by-step explanation:
Since we have given that
The scale is 1 in : 40 ft. i.e. Model : Actual.
The actual distance of the wingspan = 211 feet
Let the model of the wing be x
i.e.
[tex]\frac{1}{40}=\frac{x}{211}\\\\1\times 211=x\times 40\\\\x=\frac{211}{40}\\\\x=5.275 in[/tex]
So, the wings of the model will be 5.275 in.
