To find the area of the given traingle we have to draw perpendicular from point 'J' which meets the x axis at point (2,0) and let us named it 'P'.
As we know that area of triangle is
[tex] = \frac{1}{2}\times b \times h [\tex]
Here base 'b' will be LK and height 'h' will be JP
Here,
LK= 4 units JP=4 units
Area ={1}{2} *(4)*(4)
On solving the equation we get,
Area=8 Sq units
