Answer:
Height of ramp = 17.49 m
Explanation:
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering horizontal motion of skier
Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.
[tex]63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds[/tex]
The vertical distance traveled in 1.909 seconds is the height of ramp
Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8 [tex]m/s^2[/tex], time = 1.909 s and we need to find displacement.
[tex]s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m[/tex]
So height of ramp = 17.49 m
