The dimension of dresser is :
Length is 6.0 feet
width is 3.0 feet
The dimension of bed is :
Length is [tex]5\sqrt{2}[/tex] = 7.1 feet
Width is [tex]4\sqrt{2}[/tex] = 5.7 feet
The dimension of table:
Length is [tex]2\sqrt{2}[/tex] = 2.8 feet
Width is [tex]2\sqrt{2}[/tex] = 2.8 feet
Answer:
A). Dimensions of the bed = 7.1 ft × 5.7 ft
B). Dimensions of table = 2.8 ft × 2.8 ft
C). Dimensions of the dresser = 6ft × 3ft
Step-by-step explanation:
Dimensions of the room are 14 ft by 10 ft.
We have to find the dimensions of each furniture.
First we take the bed.
Length of the bed = [tex]\sqrt{(5)^{2}+(5)^{2}}[/tex]
= [tex]\sqrt{25+25}[/tex]
= [tex]\sqrt{50}[/tex]
= 7.07 ft ≈ 7.1 ft
Width of the bed = [tex]\sqrt{4^{2}+4^{2}}[/tex]
= [tex]\sqrt{16+16}[/tex]
= [tex]\sqrt{32}[/tex]
= 5.7 ft
We take another furniture table which is in the square shape,
Side of the table = [tex]\sqrt{2^{2}+2^{2}}[/tex]
= [tex]\sqrt{8}[/tex]
= 2.8 ft
Therefore, each side of the table is 2.8 ft
Length of the dresser = 6 ft
Width of the dresser = 3 ft
