Respuesta :

Ammimochi

Step 1. Move all terms to one side

[tex]x^2-4x-9-29=0[/tex]

Step 2. Simplify [tex]x^2-4x-9-29[/tex] to [tex]x^2-4x-38[/tex]

[tex]x^2-4x-38=0[/tex]

Step 3. Use the Quadratic Formula

[tex]x=\frac{4+2\sqrt{42} }{2} ,\frac{4-2\sqrt{42} }{2 }[/tex]

Step 4. Simplify solutions

[tex]x = 2 \sqrt{42,} 2-\sqrt{42}[/tex]

mimiwhatsup

Let's solve your equation step-by-step.

[tex]x^{2}[/tex]−4x−9=29

Step 1: Subtract 29 from both sides.

[tex]x^{2}[/tex]−4x−9−29=29−29

[tex]x^{2}[/tex]−4x−38=0

Step 2: Use quadratic formula with a=1, b=-4, c=-38.

[tex]x=\frac{-b+-\sqrt{b^{2} -4ac} }{2a}[/tex]

[tex]x=\frac{-(-4)+-\sqrt({-4})^{2} -4(1)(-38)}{2(1)}[/tex]

[tex]x=\frac{4-+\sqrt{168}}{2}[/tex]

Answer:

[tex]x=2+\sqrt{42}[/tex] or x = -2 [tex]\sqrt{42}[/tex]

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