to test the points, substitute the x-coordinate into the equation and if the value of y equals the y-coordinate then the point lies on the graph
(0, [tex]\frac{1}{2}[/tex]) → y = 0 + [tex]\frac{3}{4}[/tex] = [tex]\frac{3}{4}[/tex] ≠ [tex]\frac{1}{2}[/tex]
(0 , [tex]\frac{3}{4}[/tex]) → y = [tex]\frac{3}{4}[/tex] ← on graph
([tex]\frac{3}{4}[/tex], 0) → y = [tex]\frac{3}{8}[/tex] + [tex]\frac{3}{4}[/tex] ≠ 0
([tex]\frac{3}{4}[/tex],[tex]\frac{1}{2}[/tex] → y = [tex]\frac{3}{8}[/tex] + [tex]\frac{3}{4}[/tex] ≠ [tex]\frac{1}{2}[/tex]
([tex]\frac{1}{2}[/tex], 1) → y = [tex]\frac{1}{4}[/tex] + [tex]\frac{3}{4}[/tex] = 1 ← on graph
the points (0, [tex]\frac{3}{4}[/tex]) and ([tex]\frac{1}{2}[/tex], 1) are on the graph
