Answer:
The midpoint of AB is (0.5,1).
Step-by-step explanation:
From the given graph it is clear that the vertices of the triangle ABC are A(-2,5), B(3,-3) and C(-4,-1).
If end points of a line segment are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the midpoint of that segment is
[tex]Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
We need to find the midpoint of AB.
[tex]Midpoint=(\frac{-2+3}{2},\frac{5+(-3)}{2})[/tex]
[tex]Midpoint=(\frac{1}{2},\frac{5-3}{2})[/tex]
On further simplification we get
[tex]Midpoint=(\frac{1}{2},\frac{2}{2})[/tex]
[tex]Midpoint=(0.5,1)[/tex]
Therefore the midpoint of AB is (0.5,1).
