Respuesta :
The quadratic formula is:
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
so...
[tex]x = \frac{ - ( - 1) + - \sqrt{( - 1)^{2} - 4(4)( - 7) } }{2(4)} [/tex]
so simplified from calculator work
[tex]x = \frac{1 + \sqrt{113} }{8} \: and \: \frac{1 - \sqrt{113} }{8} [/tex]
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
so...
[tex]x = \frac{ - ( - 1) + - \sqrt{( - 1)^{2} - 4(4)( - 7) } }{2(4)} [/tex]
so simplified from calculator work
[tex]x = \frac{1 + \sqrt{113} }{8} \: and \: \frac{1 - \sqrt{113} }{8} [/tex]
The solutions to the equation 4z² − z − 7 = 0 will be negative 1.2 and 1.45.
What is a quadratic equation?
The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have
The quadratic equation is given below.
4z² − z − 7 = 0
Then we have
a = 4, b = -1, and c = -7
Then solutions to the equation will be
[tex]\rm x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4* 4 * (-7)}}{2 * 4}\\\\x = \dfrac{1 \pm \sqrt{1 + 112}}{8}\\\\x = \dfrac{1 \pm \sqrt{113}}{8}[/tex]
On further solving we have
x = (1 ± 10.63) / (8)
x = 1 - 10.63 / 8 , 1 + 10.63 / 8
x = - 1.2, 1.45
More about the quadratic equation link is given below.
https://brainly.com/question/2263981
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