In the experiment of free fall bob released a bag of mass 1 lb
so here we can say that initial speed of the bag is Zero
time taken by the bag to free fall is given as
t = 1.5 s
also the acceleration of free fall is given as
a = 9.8 m/s^2
now we will use kinematics equation here for finding the distance of free fall
[tex]d = v_i * t + \frac{1}{2} at^2[/tex]
[tex]d = 0 + \frac{1}{2}*9.8* 1.5^2[/tex]
[tex]d = 4.9 * 2.25[/tex]
[tex]d = 11.025 m[/tex]
so the bag will fall down by total distance of 11.025 m from its initial released position.