Respuesta :
Answer:
$5000*0.816 = $4082
Step-by-step explanation:
It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:
* For 3 days she was able to get 2 good shots (typical of that time of the year)
* Good shots happen randomly
* Each day is independent of another
Let's call 'p' the probability that she makes a good shot per day
Let's call 'n' the number of days Karen is taking shots.
So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:
[tex]E(x)=\frac{2}{3}[/tex]
For a Poisson distribution [tex]E (x)=\lambda\\\lambda= np[/tex]
So:
[tex]\lambda =\frac{2}{3}[/tex]
For a Poisson distribution the standard deviation is:
[tex]\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}[/tex]
[tex]\sigma = 0.816[/tex] this is the standard deviation for the number of buentas taken.
So the standard deviation for income is the price of each shot per sigma
$5000*0.816 = $4082, which is the desired response.