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using an equation or inequality to solve the problem associated with the scenario:

A rectangle has a length at least four more than five times the width. If the perimeter is at least 44 units, find the least possible width.

Respuesta :

Where w=width, l=length

perimeter = 2w + 2l

44 ≥ 2w + 2(5w+4)

44 ≥ 2w + 10w+8

44 ≥ 12w + 8

44(-8) ≥ 12w +8 (-8)

36 ≥ 12w

36 (÷12) ≥ 12w(÷12w)

3 ≥ w

least possible width is 3


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