Graph [tex]f(x) = x^2[/tex]
quadratic function is of the form [tex]f(x) = ax^2 + bx +c[/tex]
In our f(x) there is no x term and constant so we put 0
[tex]f(x) = 1x^2+0x+0[/tex]
The value of a=1 , b=0 and c=0
To find vertex , use formula [tex]x= \frac{-b}{2a}[/tex]
Plug in the values
[tex]x= \frac{-0}{2(1)}[/tex] =0
Now plug in x=0 in f(x) equation
[tex]f(x) = x^2[/tex]
[tex]f(0) = 0^2[/tex]=0
So vertex is (0,0)
Now we pick some number for x below and above 0
Make a table
x y=x^2
-2 4
0 0
2 4
Now plot all the points (-2,4) (0,0) and (2,4)
The graph is attached below
