This is a cubic form. I am assuming this should be factored.
With cubics like this it's worthwhile trying to find one root by simply guessing. My guess that worked out is x=-2
To verify:
3(-2)^3+7(-2)^2+(-2)-2 = 0 -> so -2 is a root and we get the first factor: (x+2)
Next we divide the cubic by the factor (x+2). I let you do the division. Here is the result
(3x^3 +7x^2 +x -2):(x+2) = (3 x^2 + x - 1)
(3 x^2 + x - 1) is a quadratic form and you can use the quadratic formula to get the two other roots. I got [tex]\frac{-1\pm \sqrt{13}}{6}[/tex].
So the entire cubic is now factored as follows:
[tex](x+2) \cdot (x+ \frac{-1+ \sqrt{13}}{6}) \cdot (x+ \frac{-1- \sqrt{13}}{6})[/tex]
