Answer:
To prove diagonals of a rectangle bisect each other.
It is always better to take multiple of 2.
For example A(0,0), B( 2 x,0), C(2 x, 4 x), D(0,4 x).where x is any integer.
as,⇒ AB=CD, and BC=AD,[opposite sides are equal]
⇒ Diagonal AC=Diagonal BD
⇒Sides are perpendicular to one another.
So ABCD is a rectangle.
Mid point of AC=[tex][\frac{2x+0}{2},\frac{0+4x}{2}][/tex]
=(x,2 x)
Mid point of B D=[tex][\frac{0+2 x}{2},\frac{4 x+ 0}{2}][/tex]
=(x,2x)
Which shows that diagonals of rectangle bisect each other.
If you will take all vertices as a multiple of 6 that will be excellent.
