Answer:
For the temperature to be below 32 F, following inequality must be met,
[tex]h\geq 9.333[/tex]
Step-by-step explanation:
Let "t" be the temperature at any time.
General format of a linear equation can be given as,
y= mx + c
Where,
y ⇒ dependent variable ( in this case temperature t)
m⇒ Gradient ( the rate at which the temperature drops)
x⇒ independent variable ( hours )
c⇒ intercept ( this is the starting temperature)
Now we can substitute the given values to the above format to arrive at the equation,
[tex]t=-3h+60[/tex]
We can re-arrange the equations as ,
[tex]3h=60-t[/tex]
=[tex]h=20-\frac{t}{3}[/tex]
We can write this as an inequality when t = 32 F
[tex]h\geq 20-\frac{32}{3}[/tex]
=[tex]h\geq \frac{28}{3}[/tex]
=[tex]h\geq 9.333[/tex]
