As given,
Current value = [tex]1.2\times10^{7}[/tex] dollars
Twenty years ago value was = [tex]9.6\times10^{5}[/tex] dollars
suppose x times the investment has increased, so,
[tex]9.6\times10^{5}[/tex]*x=[tex]1.2\times10^{7}[/tex]
x = [tex]\frac{1.2\times10^{7}} {9.6\times10^{5}}[/tex]
this gives x = 12.5 times.
Hence, option B is the correct answer.
