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Which line is a graph of the equation: 2x + 5y = –10? Number graph ranging from negative five to five on the x axis and negative six to two on the y axis. Four lines are drawn in blue on the graph. Lines a and c have a positive slope and are parallel to each other. Lines b and d have a negative slope and are parallel to each other. Lines a and b intersect at (zero, two), and lines c and d intersect at (zero, negative two). A. line a B. line b C. line c D. line d

Respuesta :

First we find the slope of the given line by using slope intercept form.

Converting the equation into slope intercept form

[tex] 5y=-2x-10[/tex]

Divide both side by 5 we get

[tex] y==-\frac{2}{5}-2[/tex]

On comparing with [tex] y=mx+c[/tex]


We get slope [tex] m=-\frac{2}{5}[/tex]

as the slope of line is negative therefore the line will either "b" or "d"

As line "b" pass from (0,2)

On putting it in given equation we get


[tex] 2(0)+5(2)=10[/tex]

Which is not equL to RHS of the line

Therefore b is not the given line


Now putting point (0,-2)

We get [tex] 0+5(-2)=-10[/tex]

Satisfy the equation and line "d" pass from it


There the give equationis of line "d"

Answer:the answer is line D

Step-by-step explanation:took the test and got it right

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