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In Antoine Lavoisier’s classic experiment, mercuric oxide is heated in a sealed container. The solid red powder is changed into two products: silver liquid mercury and oxygen gas. If Lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury, how much oxygen would be released? A) 7 grams B) 16 grams Reactivate C) 32 grams D) 93 grams

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Answer:

A ) 7 GRAMS

Explanation:

7 grams.

The sum of the reactants must equal the sum of the products.

Reactant = 100 grams

Products = 100 g mercuric oxide - 93 g mercury which equals 7 grams oxygen.

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