The final table is in the attached picture.
Before beginning, you should note that:
To get rid of a fraction, this fraction should be multiplied that is equal to or is a multiple of its denominator.
This means that:
[tex]\frac{1}{y} * ay = a[/tex]
Now, for the given:
We have the equation: [tex]y = \frac{1}{3} x + 2[/tex]
The denominator of the fraction is 3, therefore to get rid of it we will need x to be a 3 or a multiple of 3.
Let's consider the x values to be -3, 0, 3 and 6.
For x = -3: [tex]y = \frac{1}{3} (-3) + 2[/tex] = -3 + 2 = -1 .....>First order pair is (-3,-1)
For x = 0: [tex]y = \frac{1}{3} (0) + 2[/tex] = 0 + 2 = 2 .....> Second order pair is (0,2)
For x = 3: [tex]y = \frac{1}{3} (3) + 2[/tex] = 1 + 2 = 3 .....> Third order pair is (3,3)
For x = 6: [tex]y = \frac{1}{3} (6) + 2[/tex] = 2 + 2 = 4 .....> Fourth order pair is (6,4)
Hope this helps :)
