Answer:
The formula that can be used to describe the sequence is:
[tex]f(x)=-3\cdot (\dfrac{-1}{5})^{x-1}[/tex]
Step-by-step explanation:
We are given a sequence of numbers as:
[tex]-3\ ,\ \dfrac{3}{5}\ ,\ \dfrac{-3}{25}\ ,\ \dfrac{3}{125}\ ,\ \dfrac{-3}{625}[/tex]
Hence, we could observe that the series is a series with alternating sign such that the power of 5 is increasing in the denominator and there is no change in the numerator i.e. the power of 3 remain unchanged.
Hence,third and last option are discarded.
Also, in first option each of the terms of the digit will be negative and not alternating and hence option (1) is also discarded.
Hence, the function that represent this sequence is:
[tex]f(x)=-3\cdot (\dfrac{-1}{5})^{x-1}[/tex]
