Please show work and help!! Will give brainliest!!

Step 1. Since the power of 2 is even, the result will be positive
(3j^2k^3)^2(2j^2k)^3
Step 2. Use Multiplication Distributive Property
3^2(j^2)^2(k^3)^2(2j^2k)^3
Step 3. Simplify 3^2 to 9
9(j^2)^2(k^3)^2(2j^2k)^3
Step 4. Use the Power Rule
9j^4(k^3)^2(2j^2k)^3
Step 5. Use the Power Rule
9j^4k^6(2j^2k)^3
Step 6. Use Multiplication Distributive Property
9j^4k^6 * 2^3(j^2)^3 k^3
Step 7. Simplify 2^3 to 8
9j^4k^6 * 8(j^2)^3 k^3
Step 8. Use the Power Rule
9j^4k^6 * 8j^6k^3
Step 9. Take out the constants
(9 * 8)j^4j^6k^6k^3
Step 10. Simplify 9 * 8 to 72
72j^4k^6k^3
Step 11. Use the Product Rule
72j^4+6k^6+3
Step 12. Simplify 4 + 6 to 10
72j^10k^6 + 3
Step 13. Simplify 6 + 3 to 9
72j^10k^9