(-3j²k³)²(2j²k)³
(-3j²k³)²(2j²k)³ = When a power is raised to a power the exponents have to be multiplied.
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = We can take out the constants
= (9)(8)(j⁴k⁶)(j⁶k³) = We can group the same variables
= 72(j⁴j⁶)(k⁶k³) = When multiplying two powers that have the same base, you have to add the exponents.
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
[tex]\textit{\textbf{Spymore}}[/tex]
